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## Length and breadth of a rectangle are in the ratio 5:4. Find its perimeter if its area is 180 cm² ?

A. 98 cm

B. 12 cm**C. 54 cm**D. 27 cmLet the length and breadth be 5x cm and 4x cm.

5x*4x=180

20x²=180

x²=9,x=3 Length = 15cm Breadth = 12cm Perimeter

= 2(l+b)

= 2*27## Plan for a rectangular area is drawn to a scale of 1:500. If the length and breadth in the plan is 30 cm and 20 cm, find the actual area ?

A. 12000 m²

**B. 15000 m²**C. 1200 m²

D. 1500 m²= 30*500 cm Actual breadth

= 20*500 cm Actual area

= 30*20*500*500 = 15000 m²## A car can travel 360km with a ¾ full tank. How many km can it travel with a 2/3 full tank ?

A. 240

B. 300**C. 320**D. 400360*4/3 = 480 km With 2/3 full tank, it can travel

480*2/3 = 320 km## If the ratio of the speeds of A and B to cover a distance of 200 m is 3:4, then the ratio of the time taken to cover the same distance is ?

**A. 4:3**B. 5:4

C. 6:8

D. 3:7If the ratio of the speeds of two objects is a:b, then the time taken by them to cover the same distance is

b:a Hence, the answer is 4:3## Zufiqar can cover a distance of 400 metres in 2 minutes. Adnan can cover 1 km in 300 seconds. Find the ratio of their speeds ?

A. 1:2

**B. 1:1**C. 2:5

D. 4:3Adnan speed = 1000/300 = 3.33 m/s

Hence Ratio = 1:1## Two trains 140 metres and 120 metres are running in the same direction with speeds 40 kmph and 60 kmph respectively. In what time will the faster train pass the slower one ?

**A. 0.78 minutes**B. 0.42 minutes

C. 0.60 minutes

D. 0.36 minutesTotal distance = addition of length of the two trains = 140 + 120 = 260 metres

As the two trains are travelling in the same direction, their relative speed is:

v = | v1 – v2 | = | 40 – 60 | = 20 km/hr = 20*1000/60 = 1000/3 metres/min

t = 260/ 1000*3

t = 0.78 minutes## A man travels a distance of 2 km by walking at a speed of 6 km/hr. He returns back at a speed of 4 km/hr. What is his average speed ?

A. 5 kmph

B. 5.1 kmph**C. 4.8 kmph**D. 4.5 kmph= 2/6 = (1/3) hrs Time taken for the return journey

= 2/4 = (1/2) hrs Total time = 5/6 hrs Average speed = 4/(5/6) = 24/5 = 4.8kmph## In a journey of 24 miles, two thirds of the distance was travelled with a speed of 40 mph and the remaining with 60 mph. How much time did the journey take ?

A. 28.8 minutes

**B. 32 minutes**C. 14.4 minutes

D. 20 minutes(2/3)*24=16 miles Time taken to cover the first 16 miles

= (16/40) hours

= 24 minutes Time taken to cover the next 8 miles

= (8/60) hours

= 8 minutes Time taken for the entire journey

= 32 minute## A man takes 5 hours 45 min in walking to a certain place and riding back. He would have gained 2 hours by riding both ways. The time he would take to walk both ways is ?

**A. 7 hrs 45 min**B. 9 hts 20 min

C. 11 hrs

D. 8 hrs 45 mintime needed for riding one way = time needed for waking one way – 2 hours

Given that time taken in walking one way and riding back = 5 hours 45 min

Hence The time he would take to walk both ways = 5 hours 45 min + 2 hours = 7 hours 45 min## A car travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. What is the average speed for the first 320 km of the tour ?

A. 74. 24 km/hr

B. 72.21 km/hr

C. 70.24 km/hr**D. 71.11 km/hr**