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Third proportional to 3.5, 5.6 is ____ ?
A. 15.7
B. 19
C. 7
D. 8.963.5/5/6 = 5.6/x ; x = 5.6 * 5.6 / 3.5 = 8.96
Ratio of two numbers is 5:9. If each number is decreased by 5, the ratio becomes 5:11. Find the numbers ?
A. 15, 34
B. 15, 27
C. 30, 19
D. 21, 37(5x-5)/(9x-5) = 5:11
(5x-5)*11 = (9x-5)*5
55x – 55 = 45x – 25
10x = 30
x = 3
Therefore, the numbers are 15 and 27.Divide Rs.2000 into two shares in the ratio 3:2 ?
A. Rs.1500,Rs.500
B. Rs.1100, Rs.900
C. Rs.1200,Rs.800
D. Rs.800,Rs.12003x+2x=2000 5x=2000 x=400 3x=1200 2x=800
A bag contains 1 rupee, 2 rupee and 5 rupee coins amounting to Rs.264. If the ratio of the number of these coins is 3:5:4, find the number of 1 rupee coins ?
A. 13
B. 76
C. 41
D. 24Let the number of 1 rupee, 2 rupee and 5 rupee coins be 3x, 5x and 4x. (1*3x)+(2*5x)+(5*4x)=264 3x+10x+20x=264 33x=264 x=8 No. of 1 rupee coins
= 3x = 24If x% of 200=y% of 250, find y:x ?
A. 4:5
B. 2:5
C. 5:4
D. 5:2(x/100)*200 = (y/100)*250 y/x = 20/25 = 4/5 y:x=4:5
In a partnership for a business, Changaz invests Rs.6000 for complete year & Nasir invests Rs.3000 for 6 months. What is Nasir’s share if they earn Rs.240 as profit ?
A. 12
B. 48
C. 120
D. 192for T2 time and his share of profit is P2, then, C1 * T1 / C2 * T2 = P1/P2
If P is the Nasir’s share of profit, then Changaz gets (240 – P)
Therefore, 6000 * 12 / 3000 * 6 = (240 – P) / P = 72/ 18 = 4
4P = (240 – P)
5P = 240
P = 48A class has 90 students. If the ratio of boys and girls is 7:8, find the number of boys in the class ?
A. 23
B. 76
C. 93
D. 427x+8x=90 15x=90 x=6 Number of boys=7x=42
Ratio of boys and girls in a class was 11:13. 8 girls and 4 boys join the class from this academic year and the ratio becomes 4:5. Find the strength of the class ?
A. 108
B. 67
C. 96
D. 34= 11x+13x+4+8
= 24x+12 (11x+4):(13x+8) = 4:5 5*(11x+4)=4*(13x+8) 55x+20=52x+32 3x=12 x=4 24x+12=108Perimeter of a triangle is 81 cm. If the sides are in the ratio 4:3:2, find the length of the largest side ?
A. 27 cm
B. 36 cm
C. 45 cm
D. 40 cmLet the three sides be 4x,3x and 2x. 4x+3x+2x = 81 9x = 81 x = 9 Length of the largest side
= 4x = 36 cmM:N = 3:4, N:O = 5:7 and O:P = 7:9. Then M:P = ?
A. 5/12
B. 1/6
C. 1/3
D. 7/9M/P = M/N * N/O * O/P = ¾ * 5/7 * 7/9 = 5/ 12