Basic Mathematics MCQs with answers cover topics such as Math MCQs PDF, Math MCQs with answers PDF, Basic Mathematics MCQs with answers, averages, areas, percentages, solving math problems, all mathematical formulas, basic algebra, basic math, arithmetic, and geometry MCQs. These Math MCQs range from basic to advanced levels, providing preparation for tests. Includes Mathematics MCQs PDF, Basic Mathematics MCQs with solutions PDF for download, Mathematics MCQs online test, and Math MCQs for PPSC, FPSC, NTS, SPSC, PTS, OTS, KPPSC, BPSC, and ETEA past papers.

## Third proportional to 3.5, 5.6 is ____ ?

A. 15.7

B. 19

C. 7**D. 8.96**3.5/5/6 = 5.6/x ; x = 5.6 * 5.6 / 3.5 = 8.96

## Ratio of two numbers is 5:9. If each number is decreased by 5, the ratio becomes 5:11. Find the numbers ?

A. 15, 34

**B. 15, 27**C. 30, 19

D. 21, 37(5x-5)/(9x-5) = 5:11

(5x-5)*11 = (9x-5)*5

55x – 55 = 45x – 25

10x = 30

x = 3

Therefore, the numbers are 15 and 27.## Divide Rs.2000 into two shares in the ratio 3:2 ?

A. Rs.1500,Rs.500

B. Rs.1100, Rs.900**C. Rs.1200,Rs.800**D. Rs.800,Rs.12003x+2x=2000 5x=2000 x=400 3x=1200 2x=800

## A bag contains 1 rupee, 2 rupee and 5 rupee coins amounting to Rs.264. If the ratio of the number of these coins is 3:5:4, find the number of 1 rupee coins ?

A. 13

B. 76

C. 41**D. 24**Let the number of 1 rupee, 2 rupee and 5 rupee coins be 3x, 5x and 4x. (1*3x)+(2*5x)+(5*4x)=264 3x+10x+20x=264 33x=264 x=8 No. of 1 rupee coins

= 3x = 24## If x% of 200=y% of 250, find y:x ?

**A. 4:5**B. 2:5

C. 5:4

D. 5:2(x/100)*200 = (y/100)*250 y/x = 20/25 = 4/5 y:x=4:5

## In a partnership for a business, Changaz invests Rs.6000 for complete year & Nasir invests Rs.3000 for 6 months. What is Nasir’s share if they earn Rs.240 as profit ?

A. 12

**B. 48**C. 120

D. 192for T2 time and his share of profit is P2, then, C1 * T1 / C2 * T2 = P1/P2

If P is the Nasir’s share of profit, then Changaz gets (240 – P)

Therefore, 6000 * 12 / 3000 * 6 = (240 – P) / P = 72/ 18 = 4

4P = (240 – P)

5P = 240

P = 48## A class has 90 students. If the ratio of boys and girls is 7:8, find the number of boys in the class ?

A. 23

B. 76

C. 93**D. 42**7x+8x=90 15x=90 x=6 Number of boys=7x=42

## Ratio of boys and girls in a class was 11:13. 8 girls and 4 boys join the class from this academic year and the ratio becomes 4:5. Find the strength of the class ?

**A. 108**B. 67

C. 96

D. 34= 11x+13x+4+8

= 24x+12 (11x+4):(13x+8) = 4:5 5*(11x+4)=4*(13x+8) 55x+20=52x+32 3x=12 x=4 24x+12=108## Perimeter of a triangle is 81 cm. If the sides are in the ratio 4:3:2, find the length of the largest side ?

A. 27 cm

**B. 36 cm**C. 45 cm

D. 40 cmLet the three sides be 4x,3x and 2x. 4x+3x+2x = 81 9x = 81 x = 9 Length of the largest side

= 4x = 36 cm## M:N = 3:4, N:O = 5:7 and O:P = 7:9. Then M:P = ?

**A. 5/12**B. 1/6

C. 1/3

D. 7/9M/P = M/N * N/O * O/P = ¾ * 5/7 * 7/9 = 5/ 12