Basic Maths MCQs with answers PDF for Mathematics. Includes Math MCQs for all competitive exams like PPSC, FPSC, NTS, ETEA exams, and police past papers. Features Math MCQs test, Basic Math MCQs online test, and FPSC Math MCQs PDF.
A can lay a railway track between two given stations in 16 days and B can do the same job in 12 days. With help of C, they did the job in 4 days only. Then, C alone can do the job in ____ ?
A. 9.6
B. 6
C. 12
D. 23Part of work completed by A and B in 4 days
= 4*((1/16) + (1/12))
= 7/12 C can complete 5/12th of the work in 4 days C can complete the whole job in
4÷(5/12) = 9.6 daysTwelve men can do a work in twenty days while twenty women can finish the same work in sixteen days. Find the ratio between the capacity of a man and a woman ?
A. 5:3
B. 4:3
C. 3:4
D. 5:4Part of work completed by a man in a day = 1/(12*20)
= 1/240 Part of work completed by a woman in a day = 1/(20*16) = 1/320 Ratio of their capacities
= (1/240):(1/320) = 320:240 = 4:3A and B can do a piece of work in 12 days; B and C in 15 days; C and A in 20 days. A alone can do the work in ____ ?
A. 60 days
B. 50 days
C. 40 days
D. 30 daysA tap can fill a tank in 32 min. and another can empty it in 16 min. If the tank is already half full and both the tanks are opened together, the tank will be ____ ?
A. 16 min
B. 24 min
C. 12 min
D. 7 minA leak in the bottom of a tank can empty the full tank in 6 hrs. An inlet pipe fills water at the rate of 4 lit. a minute. When the tank is full, the inlet is opened and due to the leak, the tank is empty in 8 hrs. The capacity of the tank in liters is ____ ?
A. 6,890 litres
B. 5,750 litres
C. 5,760 litres
D. None of themP can do a work in the same time in which Q and R together can do it. If P and Q work together, the work can be completed in 10 days. R alone needs 50 days to complete the same work. then Q alone can do it in _____ ?
A. 25 days
B. 15 days
C. 30 days
D. 20 daysWork done by P and Q in 1 day = 1/10
Work done by R in 1 day = 1/50
Work done by P, Q and R in 1 day = 1/10 + 1/50 = 6/50
But Work done by P in 1 day = Work done by Q and R in 1 day . Hence the above equation can be written as
Work done by P in 1 day × 2 = 6/50
=> Work done by P in 1 day = 3/50
=> Work done by Q and R in 1 day = 3/50
Hence work done by Q in 1 day = 3/50 – 1/50 = 2/50 = 1/25
So Q alone can do the work in 25 days10 men can complete a work in 7 days. But 10 women need 14 days to complete the same work. How many days will 5 men and 10 women need to complete the work ?
A. 4
B. 7
C. 12
D. 17Work done by 10 men in 1 day = 1/7
Work done by 1 man in 1 day = (1/7)/10 = 1/70
Work done by 10 women in 1 day = 1/14
Work done by 1 woman in 1 day = 1/140
Work done by 5 men and 10 women in 1 day = 5 × (1/70) + 10 × (1/140)
= 5/70 + 10/140 = 1/7
=> 5 men and 10 women can complete the work in 7 daysP and Q need 8 days to complete a work. Q and R need 12 days to complete the same work. But P, Q and R together can finish it in 6 days. How many days will be needed if P and R together do it ?
A. 3
B. 15
C. 25
D. 8Let work done by P in 1 day = p
work done by Q in 1 day =q
Work done by R in 1 day = r
p + q = 1/8 —(1)
q + r= 1/12 —(2)
p+ q+ r = 1/6 —(3)
(3) – (2) => p = 1/6 – 1/12 = 1/12
(3) – (1) => r = 1/6 – 1/8 = 1/24
p + r = 1/12 + 1/24 = 3/24 = 1/8
=> P and R will finish the work in 8 daysRunning at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes ?
A. 1800
B. 450
C. 2700
D. 1080= 270/6 Number of bottles produced by 10 machines in 4 minutes
= (270/6)*10*4 = 1800A alone can finish a work in X days. B alone can finish the same work in X+5 days. Together, they take 6 days to complete the work. Find X ?
A. 5
B. 17
C. 35
D. 10Part of work completed by A in a day = 1/X Part of work completed by B in a day
= 1/(X+5) (1/X)+(1/(X+5)) = 1/6 (2X+5)/(X²+5X) = 1/6 X²+5X = 6(2X+5) X²-7X-30=0 Solving, X=10