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Ten years ago, the age of Usman was one-third the age of Majeed at that time. The present age of Majeed is 12 years more than the present age of Usman. Find the present age of Usman ?
A. 16
B. 22
C. 43
D. 71Let the present ages of Aftab and Kashif be ‘a’ and ‘b’ respectively.
a – 10 = 1/3 (b – 10) — (1)
b = a + 12
Substituting b = a + 12 in first equation,
a – 10 = 1/3 (a + 2) => 3a – 30 = a + 2
=> 2a = 32 => a = 16.Sum of four consecutive even numbers is 292. What would be the smallest number ?
A. 23
B. 45
C. 67
D. 70Let the four consecutive even numbers be 2(x – 2), 2(x – 1), 2x, 2(x + 1)
Their sum = 8x – 4 = 292 => x = 37
Smallest number is: 2(x – 2) = 70.Cost of 16 pens and 8 pencils is Rs.352 and the cost of 4 pens and 4 pencils is Rs.96. Find the cost of each pen ?
A. Rs.76
B. Rs.67
C. Rs.32
D. Rs.2016p + 8q = 352 — (1)
4p + 4q = 96
8p + 8q = 192 — (2)
(1) – (2) => 8p = 160
=> p = 20P, Q and R have Rs.6000 among themselves. R has two-thirds of the total amount with P and Q. Find the amount with R ?
A. Rs.3600
B. Rs.4000
C. Rs.3000
D. Rs.2400Let the amount with R be Rs.r
r = 2/3 (total amount with P and Q)
r = 2/3(6000 – r) => 3r = 12000 – 2r
=> 5r = 12000 => r = 2400.Eight years ago, Zahid’s age was 4/3 times that of Jabbar. Eight years hence, Zahid’s age will be 6/5 times that of Jabbar. What is the present age of Zahid ?
A. 40 years
B. 48 years
C. 30 years
D. 32 yearsZ – 8 = 4/3 (S – 8) and Z + 8 = 6/5 (S + 8)
3/4(Z – 8) = S – 8 and 5/6(Z + 8) = S + 8
S = 3/4 (Z – 8) + 8 = 5/6 (Z + 8) – 8
=> 3/4 Z – 6 + 8 = 5/6 Z + 20/3 – 8
=> 10 – 20/3 = 10/12 Z – 9/12 Z
=> 10/3 = Z/12 => Z = 40.There are some rabbits and peacocks in a zoo. The total number of their heads is 60 and total number of their legs is 192. Find the number of total rabbits ?
A. 24
B. 56
C. 98
D. None of themone head, so r + p = 60 — (1)
Each rabbit has 4 legs and each peacock has 2 legs. Total number of legs of rabbits and peacocks, 4r + 2p = 192 — (2)
Multiplying equation (1) by 2 and subtracting it from equation (2), we get
=> 2r = 72 => r = 36.Three consecutive odd integers are in increasing order such that the sum of the last two integers is 13 more than the first integer. Find the three integers ?
A. 7, 9, 11
B. 13, 15, 17
C. 9, 11, 13
D. 11, 13, 15Let the three consecutive odd integers be x, x + 2 and x + 4 respectively.
x + 4 + x + 2 = x + 13 => x = 7
Hence three consecutive odd integers are 7, 9 and 11.A bag contains equal number of Rs.5, Rs.2 and Re.1 coins. If the total amount in the bag is Rs.1152, find the number of coins of each kind ?
A. 144
B. 72
C. 432
D. 288If ‘a’ denotes the unknown value and is increased by 2, the result will be 12 then the equation for this statement will be _____ ?
A. a = 12 + 2
B. a – 2 = 12
C. a + 2 = 12
D. 2a = 12Four handbags and three school bags costs $2000 and cost of handbag is thrice as much as schoolbags. If cost of school bag is ‘a’ then the derived equation will be _____ ?
A. 3(4a) + 3(3a) = 2000
B. 3(4a) – 3(3a) = 2000
C. 3(4a) – 3a = 2000
D. 3(4a) + 3a = 2000