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Fresh fruit contains 68 % water and dry fruit contains 20 % water. How much dry fruit can be obtained from 100 kg of fresh fruits ?
A. 52 kg
B. 80 kg
C. 32 kg
D. 40 kgFresh grapes contain 80 % water dry grapes contain 10 % water. If the weight of dry grapes is 250 kg. What was its total weight when it was fresh ?
A. 1100 kg
B. 1225 kg
C. 1125 kg
D. 1000 kgQuantity of water in it = (80/100 × x)kg = 4x/5 kg
Quantity of pulp in it = (x – 4x/5)kg = x/5 kg
Quantity of water in 250 kg dry grapes
= (10/100 × 250)kg = 25kg
Quantity of pulp in it = (250 – 25)kg = 225 kg
Therefore, x/5 = 225
=> x = 1125
Quality of water that should be added to reduce 9 ml. Lotion containing 50 % alcohol to a lotion containing 30 % alcohol is ?
A. 6 ml
B. 5 ml
C. 3 ml
D. 4 mlIn two successive years, 100 and 75 students of a school appeared at the final examination. Respectively 75 % and 60 % of them passed. The average rate of pass is ?
A. 80 %
B. 80 4/7 %
C. 68 4/7 %
D. 78 %Of the 1000 inhabitants of a town 60 % are males of whom 20 % are literate. If of all the inhabitants 25 % are literate. Then what percent of the females of the town are literate ?
A. 27.5 %
B. 37.5 %
C. 22. 5 %
D. 32. 5 %Males = (60/100 × 1000) = 600,
females = (1000 – 600) = 400
Literate males = (20/100 × 600) = 120
Total literates = (25/100 × 1000) = 250
Female literates = (250 – 120) = 130
Required % = (130/400 × 100)% = 32.5 %
Sum of two numbers is 2490. If 6.5 % of one number is equal to 8.5 % of the other then the numbers are ?
A. 1011, 1479
B. 1401, 1089
C. 1411, 1079
D. 989, 1501Then 6.5 % of x = 8.5 % of (2490 – x)
=> 6.5/100 × x = 8.5/100 × (2490 – x)
=> 65x/1000 = 85(2490 – x)/1000
=> 65x = (85 × 2490) – 85x
=> 150x =(85 × 2490)
=> x = 211650/150 = 1411
Hence the numbers are 1411 and (2490 – 1411) = 1079
A reduction of 20 % in the price of rice enables a person to buy 3.5 kg more rice for Rs. 385. The original price of rice is ?
A. Rs. 27.50 per kg
B. Rs. 25 per kg
C. Rs. 20 per kg
D. Rs. 22.50 per kg8 % of the voters in an election did not cast their votes in the election, there were only two candidates. The winner by obtaining 48 % of the total votes defeated his contestant by 1100 votes. The total number of voters in the election was ?
A. 27500
B. 23500
C. 21000
D. 2200Votes cast = 92 % of x = (92/100 × x) = 23x/25
Votes in favour of winning candidate = 48/100 × x
= 12x/25
Votes polled by defeated candidate = (23x/25 – 12x/25)
= 11x/25 12x/25 – 11x/25 = 1100
=> 12x – 11x = 27500
=> x = 27500
What will be the ratio of simple interest earned by certain amount at the same rate of interest for 6 years and that for 9 years?
A. 8 : 4
B. 2 : 3
C. 1 : 3
D. 1 : 4Let the principal be P and rate of interest be R%. So Required ratio = [(P x R x 6/100) / (13 x R x 9/100)] = 6PR/9PR = 6/9 = 2 : 3
A sum of Rs. 12,500 amounts to Rs. 15,500 in 4 years at the rate of simple interest What is the rate of interest?
A. 6%
B. 5%
C. 3%
D. 4%