Percentage mcqs with answers pdf for FPSC NTS PPSC SPSC BPSC, KPPSC and ETEA. Percentage Questions with solutions PDF and mathematics mcqs with answers pdf.
In an examination, 65 % of the total examinees passed if the number of failures is 420, the total number of examinees is ?
A. 1200
B. 2450
C. 1360
D. 200Percentage of failure = (100 – 65) % = 35 %
Let the total number of examinees be x.
Then 35 % of x = 420
=> 35/100 × x = 420
=> x =(420 × 100/35) = 1200
Out of an earning of Rs. 720 Ram spends 65 %. How much does he save ?
A. Rs. 390
B. Rs. 316
C. Rs. 252
D. Rs. 350Savings % = (100 – 65) % = 35 %
Saving = 35 % of Rs. 720
= Rs(35/100 ×720) = Rs. 252
Ratio of the number of boys and girls is 3:2 if 20 % of the boys and 30 % of the girls are scholarship holders then the percentage of students who do not get scholarship is ?
A. 79
B. 76
C. 24
D. 56Let the number of boys be 3x and number of girls be 2x.
Number of scholarship holders
= (20/100 ×3x+ 30/100 ×2x) = 6x/5
Number of those who do not hold scholarship
= (5x- 6x/5) = 19x/5
Required percentage = (19x/5 × 1/5x ×100) % = 76 %
In 50 gm alloy of gold and silver the gold is 80 % by weight. How much gold should be mixed with this alloy so that the weight of gold would become 95 % ?
A. 50 gm
B. 10 gm
C. 200 gm
D. 150 gmA reduction of 20 % in the price of sugar enables a purchaser to obtain 3kg more for Rs. 120. The original price of sugar per kg is ?
A. Rs. 10
B. Rs. 8
C. Rs. 15
D. Rs. 12A and B are two fixed points 5 cm apart and c is a point on AB such that AC = 3 cm. If the length of AC is increased by 6 % the length of CB is decreased by ?
A. 7 %
B. 8 %
C. 9 %
D. 6 %AC = 3cm, CB = (5 – 3)cm = 2 cm
New length AC = 106 % of 3 cm
= (106/100 ×3) cm = 3.18 cm.
New length CB = (5 – 3.18) cm = 1.82 cm
CB Decreased on 2cm = (2 – 1.82)cm = 0.18cm
CB Decrease % = (0.18/2 ×100) % = 9 %
Length of a rectangle is increased by 10 % and breadth decreased by 10 % Then the area of a new rectangle is ?
A. decreased by 1 %
B. neither increased nor decreased
C. increased by 1 %
D. decreased by 10 %New length = (110/100 l) units = (11 l)/10 units
New breadth = (90/100 b) units = (9 l)/10 units
New area = (11l/10 × 9b/10) sq. Units = 99lb/100 sq. units
Decrease in area = (lb- 99lb/100)sq units = lb/100 sq. units
Decrease in area = (lb/100 × 1/lb ×100) % = 1 %
Decrease by = 1 %
A typist uses a paper 30 cm by 15 cm. He leaves a margin of 2.5 cm at the top as well as at the bottom and 1.25 cm on either side. What percentage of paper area is approximately available for typing ?
A. 80 %
B. 60%
C. 70 %
D. 65 %Total Area of the Paper = (30 × 15) Sq.cm = 450 Sq.cm
Area Used = [(30-5)×(15-2.5) ]Sq.cm
= (25 × 12.5) Sq.cm = (25 x 25/2) Sq.cm = 625/2 cm2
Percentage are Used by = (625/2× 1/450×100) %
= 69.4 % = 70 % nearly
If the side of a square is increased by 25 %. Then its area is increased by ?
A. 40.5 %
B. 56.25 %
C. 25 %
D. 55%Then it’s area = x2 sq. Units
Side of new square = 125 % of x = (125/100 × x)units = 5x/4 units
New area = (5x/4 × 5x/4)sq.units = 25×2/16 Sq.units
Increase in area = (25×2/16 – x2) = 9×2/16 Sq.Units
Increase % = (9×2/16 × 1/x2 × 100)%
= 225/4 % = 56.25 %
Two number is first increased by 10 % and then reduced by 10 % the number ?
A. 4:5
B. 3:5
C. 2:5
D. 6:7Then 1st number = 120% of x = (120/100 × x) = 6x/5
2nd number = 150 % of x = (150/100 × x) = 3x/2
Ratio of these numbers = 6x/5 : 3x/2 = 12: 15 = 4 : 5