I. x2 + 3x – 18 = 0, II. y2 + y – 30 = 0 to solve both the equations to find the values of x and y ?

– by 0

A. If x > y
B. If x ≥ y
C. If x < y
D.  If x = y or the relationship between x and y cannot be established.

Explanation:

I. x2 + 6x – 3x – 18 = 0
=>(x + 6)(x – 3) = 0 => x = -6, 3
II. y2 + 6y – 5y – 30 = 0
=>(y + 6)(y – 5) = 0 => y = -6, 5
No relationship can be established between x and y.

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