(i). a2 + 11a + 30 = 0, (ii). b2 + 6b + 5 = 0 to solve both the equations to find the values of a and b ?

– by 0

A.  If a ≤ b
B. If a > b
C. If a < b
D. If the relationship between a and b cannot be established

Explanation:

I. (a + 6)(a + 5) = 0
=> a = -6, -5
II. (b + 5)(b + 1) = 0
=> b = -5, -1 => a ≤ b

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