Ratio of the prices of three different types of cars is 4:5:7. If the difference between the costliest and the cheapest cars is Rs. 60000 the price of the car of modest price is ______ ?

– by 0

A. Rs. 140000
B. Rs. 120000
C. Rs. 80000
D. Rs. 100000

Explanation:

Let the prices be 4X, 5X and 7 X rupees

7X – 4X = 60000

=> X = 20000

Required price = 5X = Rs. 100000

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